avg of 20 numbers s zero.of them ,at most,how many may be greater than zero?

• Avg is zero,Hence the sum of these numbers must be zero.So,The 20th number could be the negative to sum of all 19nos. Hence 19 is the correct answer.
• 11 years agoHelpfull: Yes(15) No(1)
• there are 20 no.
  
  so atleast one no. should b negative to make sum of nineteen no become zero so..
  
  answer is nineteen
  
• 11 years agoHelpfull: Yes(4) No(0)
• ans:19
  ex- all 19 numbers are positive and 20th is as much as negative as all 19 are positive. this is the first and the last case.
• 11 years agoHelpfull: Yes(3) No(1)
• at most 19 nos. can be greater then zero and the sum of these 19 nos. can be the 20th no. so the 20th no. will be negative. therefore the average will be zero
• 11 years agoHelpfull: Yes(1) No(0)
• ans=19;
  assume that d first 19 no is having d value as=1
  so,to get d avg as 0 we should deduct d whole by -19.hence 19 no is there which is having d value as greater than 0.
• 11 years agoHelpfull: Yes(1) No(0)
• 19
  Average of 20 numbers = 0
  
  =>Sum of 20 numbers20=0
  
  => Sum of 20 numbers = 0
  
  Hence at the most, there can be 19 positive numbers.
  
  (Such that if the sum of these 19 positive numbers is x, 20th number will be -x)
• 11 years agoHelpfull: Yes(0) No(0)
• 14 the sum of first 14 natural nos is equal to the next six negative natural nos
• 11 years agoHelpfull: Yes(0) No(4)