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A batsman avg was 15 at the last innings he took 23 runs then his avg became 16.How much run he should have taken to make his avg 18.
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- initially batsman average 15
when 23 is added it becomes 16
so batsman has played 23-16=7 innings previously
if he should boost his average to 18 then he must score
18+(18-15)*7=18+21=39
so he must score 39 runs in 8th innings - 11 years agoHelpfull: Yes(14) No(1)
- t=total run
m=total match
t/m=15,(t+23)/(m+1)=16, solving this m=7 and t=105
now, (105+x)/8=18,therefore x=39
- 11 years agoHelpfull: Yes(9) No(0)
- initial avg=15
his average become 16 after scoring 23(15+8).
8 run extra increase 1 run avg.
to increase it 3 run he will have to score(15+8*3)=39
- 10 years agoHelpfull: Yes(2) No(0)
- 34 Runs Required to make average 18.
Let no of innigs played is X so
16(X+1)=15X+23
16X-15X=23-16
X=7
Now Total Runs when average is 16= 16(X+1)=128
Total Runs when average is 18=18(x+1+1)=162
Required Runs =162-128=34 - 11 years agoHelpfull: Yes(1) No(2)
- ANS. IS=32
- 11 years agoHelpfull: Yes(0) No(5)
- batsman initial avg=15 and no of matches be x than total run r=15x.
so r/x=15.
now in last inning (r+23)/(x+1)=16
it gives x=7 and r=105
Now to make his average 18 he needs to score.....
(105+y)/8=18(let y be the run needs to be scored)
It gives y=39
Ans :39 - 9 years agoHelpfull: Yes(0) No(0)
- if 15 to 16 average needs 23run(difrnce from avege 23-16=7) then 16 to 18=2*23=46,46-7=39
- 9 years agoHelpfull: Yes(0) No(0)
(x1+x2+x3+----------------xn)/n=15 ---------------->1
(x1+x2+x3+-----------------xn+23=16 _--------------->2
eque 2 - 1
23=16(x+1)-15x
23=16+x x=7
(x1+x2+x3+-----------------xn+x(n+1)/8 = 18
(x1+x2+x3+-----------------xn)=105
105 +x(n+1)=148
ans : 43
- 9 years agoHelpfull: Yes(0) No(0)
- avg=15
last innings=23
let no. of matches =x
sum=15x
new sum=15 - 8 years agoHelpfull: Yes(0) No(0)
- 3 runs / ball
- 7 years agoHelpfull: Yes(0) No(0)
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