Q. An alloy of zinc and copper contains the metals in the ratio 5 : 3. The quantity of zinc to be added to 16 kg of the alloy so that the ratio of the metal may be 3 : 1 is:

Option
A) 2
B) 4
C) 8
D) 3

• ans:8 kg
  5/8*16=10
  3/8*16=6
  (10+x)/6=3/1
  =8
• 11 years agoHelpfull: Yes(50) No(2)
• In sixteen kg of alloy 10 kg of zinc and 6 kg copper is present
  to make the ratio 3:1 we must add 8 kg of zinc to make it 18 kg of zinc and 6 kg copper
  so ans is 8
• 11 years agoHelpfull: Yes(25) No(0)
• in 16kg of alloy
  we'll have zinc as 10 kg and copper as 6kg
  
  now for 3:1 ratio (10+x)/6 =3/1
  
  x=8
• 11 years agoHelpfull: Yes(14) No(0)
• ans : C 8 kg
  z/c=5/3 z+c=16
  therefore z=10 c=6
  10+8=18/6=3:1
• 11 years agoHelpfull: Yes(6) No(1)
• since 5x+3x=16 so x=2 means in 16kg of alloy zinc is 10kg and copper is 6 kg clearly if we add 8kg then the mixture becomes in ratio of 3:1
• 11 years agoHelpfull: Yes(1) No(0)
• B
  zinc nd copper ratio in the metal=5:3
  so zinc ratio is 5x nd copper ratio is 3x
  when we add 16kg of zinc to the metal it becomes 3:1
  therefore
  5x+16:3x=3:1
  5x+16/3x=3/1
  5x+16=9x
  4x=16
  x=4
• 11 years agoHelpfull: Yes(1) No(5)
• 2(5:3)=10:6
  10+6=16
  2(3:1)=6:2
  6+2=8
  ans=8
  
  
• 11 years agoHelpfull: Yes(0) No(1)
• ratio is 5:3
  after added 16 kg zink ,zink will be 5+16=21
  now ratio is 3:1
  it's means copper will be 7 so 4 kg copper missed in alloy.
  
• 11 years agoHelpfull: Yes(0) No(4)
• Ans:4
  ratio of zinc:copper is 5:3
  after 16kg of zinc to be added so the ratio becomes 5x+16 : 3x
  after adding zinc tht ratio become 3:1
  so
  5x+16/3x=3/1;
  solve this equ we get 4
• 4 years agoHelpfull: Yes(0) No(0)