a long thin strip of width 10cm is kept on a flat surface.another identical strip is kept on it as an overlapping manner such that the combined width of the two is 15cm.what is the width if 22 such strips kept like this? a.115cm b.110cm c.200cm c.95cm

• Keeping first strip constant, each of 21 strips will add 5 each to the width.
  => 21*5 = 105 cm
  Adding first one , 105+10 => 115cm
  ANSWER => (a)
• 13 years agoHelpfull: Yes(15) No(2)
• for 1 strip 5cm is increased
  so, for 21 strips it is 21*5=105
  width of the first strip is 10cm
  so, for 22 strips 105+10=115cm
  hence option a is the answer
• 13 years agoHelpfull: Yes(5) No(1)
• 1st strip width is 10c.m.2nd strip width is also 10 c.m.
  Combined strip width of 1st and 2nd is 15 c.m(given).
  if 20 such strips are kept,then 20/2=10 combined stips width will be 10*15=150c.m+15c.m(1st combined strip width)=165c.m
• 13 years agoHelpfull: Yes(1) No(7)
• a)115cm 21*5=110+5(first)=115cm
• 13 years agoHelpfull: Yes(1) No(1)
• sinc for every single strip widt is increased by 5 cm
  so,for 22 strips width will be 22*5=110
  
• 13 years agoHelpfull: Yes(1) No(2)
• a. 115 just did...
• 13 years agoHelpfull: Yes(0) No(2)
• for 1 strip 5cm is increased
  so, for 21 strips it is 21*5=105
  width of the first strip is 10cm
  so, for 22 strips 105+10=115cm
  hence option a is the answer
• 11 years agoHelpfull: Yes(0) No(0)
• answer is A :because 10+(21*5)=115;
  here 1st strip width is 10;
  and 21 times 5cm increased each time.
• 7 years agoHelpfull: Yes(0) No(0)
• 115
  For two strip we are getting three 5 cm division
  Therefore for 22 strip we will get 23 division
  i.e. resultant width=23*5=115 cm
• 6 years agoHelpfull: Yes(0) No(0)