26ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =?
A. 52
B. 65
C. 10
D. 25

• Any number last two digits are 25 then that should be divisible by 25.
  When ab=52, the number is 26525 and 52/13=4,
  So ab=52
• 10 years agoHelpfull: Yes(12) No(0)
• Ques is wrong no is not 4 digit no.
• 10 years agoHelpfull: Yes(11) No(4)
• 65 65
• 10 years agoHelpfull: Yes(4) No(7)
• since ab is too be multiple of 13 so options c,d can be eliminated.
  from a,b it is clear that only when ab=52 is kept in 26ab5 gives remainder 0 when divided by 25.
  answer:A.52
• 10 years agoHelpfull: Yes(3) No(1)
• 52 obviously
• 10 years agoHelpfull: Yes(2) No(1)
• 26ab5 is not 4 digit number
• 8 years agoHelpfull: Yes(0) No(0)
• both 65 and 52 when substituted gets divisble by 25..and also both the numbers are multiples of 13
  
• 8 years agoHelpfull: Yes(0) No(3)
• wkt divisbility rule of 25=last no. should be 00,25,50,75
  let us go with options,1]...52, 26525/25=1061
  thus 52 is the ans.
• 6 years agoHelpfull: Yes(0) No(0)
• the number is 26525/25 and 52/13=4,
  So ab=52
• 5 years agoHelpfull: Yes(0) No(0)