A owes B Rs 50. He agrees to pay B over a number of consecutive day starting on a Monday, paying single note of Rs 10 or Rs 20 on each day. In how many different ways can A repay B. (Two ways are said to be different if at least one day, a note of a different denomination is given)
A. 8
B. 7
C. 6
D. 5

• 10,20,20=3!/2!==3 ways
  10,10,10,20=4!/3!==4 ways
  10,10,10,10,10=5!/5!==1 way
  so.total=3+4+1==8 ways.
• 11 years agoHelpfull: Yes(40) No(4)
• 8 ways
  Sudarshan one way is 10 10 10 10 10
• 11 years agoHelpfull: Yes(26) No(13)
• 10,20,20
  20,10,20
  20,20,10
  10,10,10,20
  10,10,20,10
  10,20,10,10
  20,10,10,10
  10,10,10,10,10
  so total ways is 8
• 11 years agoHelpfull: Yes(19) No(4)
• 10,20,20
  20,10,20
  20,20,10
  10,10,10,20
  10,10,20,10
  10,20,10,10
  20,10,10,10
  only seven possibilities as i can see..
• 11 years agoHelpfull: Yes(18) No(25)
• total 8 ways
  10 10 10 10 10
  10 10 10 10 20
  10 10 10 20 10
  10 10 20 10 10
  10 20 10 10 10
  20 10 10 10 10
  10 20 20
  20 10 20
  20 20 10
• 11 years agoHelpfull: Yes(4) No(3)
• let a = 10/- Rs , b = 20/- Rs.
  10a + 20b = 50..............
  now check the a and b's possibility to satisfy the above condition
  a = 1 , b = 2
  a = 3, b = 1
  a = 5, b = 0
  so number of combination a and b is = 3
  so total ways = 2^3 = 8 (number of arrangement)
• 9 years agoHelpfull: Yes(4) No(0)
• ans:8.....
• 11 years agoHelpfull: Yes(2) No(4)
• all 10 rupees note in 1 way =1
  3 ten rs notes+1 twenty rs notes=4 and 4!/3!=4 (where 3! denotes that 3 10 rupees notes are common)
  2 twenty rs+1 ten rupees notes=3 and 3!/2!=3 (where 2! denotes that 2 20 rupees notes are common)
  therfore 1+3+4=8 ways
• 9 years agoHelpfull: Yes(2) No(0)
• The possibility of '10 10 10 10 10' can't be occur because it is given that atleast one day a note of different denomination should be given.
  so the total no.of ways can be 7.
  10,20,20=3!/2! =>3
  10,10,10,20=4!/3! =>4
  so total no.of ways are 1+3=>7 ways
• 8 years agoHelpfull: Yes(2) No(0)
• the total ways is 8 as explained by the above people.but they have mentioned that atleast one day a different note should be given.hence we cant take 10 10 10 10 10.deducting this one way out of 8 .we get 7 ways.i hope this is the right answer
• 7 years agoHelpfull: Yes(1) No(0)
• 8..possible becsuse they condition (or)
  10,20,20
  20,10,20
  20,20,10
  10,10,10,20
  10,10,20,10
  10,20,10,10
  20,10,10,10
  10,10,10,10,10
  
• 9 years agoHelpfull: Yes(0) No(0)
• all 10's : 10 10 10 10 10 = 5!/5! = 1way
  10 10 10 20 = 4!/3! = 4ways
  10 20 20 = 3!/2! = 3ways
  total: 1 + 4 + 3 = 8ways
• 8 years agoHelpfull: Yes(0) No(0)
• all 10's : 10 10 10 10 10 = 5!/5! = 1way
  10 10 10 20 = 4!/3! = 4ways
  10 20 20 = 3!/2! = 3ways
  total: 1 + 4 + 3 = 8ways
• 8 years agoHelpfull: Yes(0) No(0)
• total 8 ways
  10 10 10 10 10
  10 10 10 10 20
  10 10 10 20 10
  10 10 20 10 10
  10 20 10 10 10
  20 10 10 10 10
  10 20 20
  20 10 20
  20 20 10
• 8 years agoHelpfull: Yes(0) No(1)