In the library, there are 10 tables, 4 chairs per table. in each table there are different numbers of people seated. how many ways they will sit in the library so that no chairs would be blank?

• 10 tables.each has 4 chairs.
  for each table different number of people are sat,so first table 1person,second table 2persons,third table 3persons,4th table 4persons.
  so people means(1+2+3+4) so 4 tables are filled so 10-4=6 reading tables does not have single reader.
• 13 years agoHelpfull: Yes(38) No(32)
• To my knowledge question should be asked as "how many ways they will sit in the library so that no chairs would be blank in a table?" at the end. Then the answer will be
  '7' which is there in the options.
  At first chance single person to sit in the table in 10 ways(10 will be there)
  For second chance two person must be seated(as different members must be seated) so no of ways they can sit is 9 (1 table will already be filled)
  For third chance 3 person must be seated and they will be left with 8 options
  Finally 4 members( which is our required condition)they will be left with 7 tables (so they can be seated in 7 ways)
  Note: Answer for this can also be 8,9,10 if we don't follow order in filling tables . But 7 is precise to this question
  
• 12 years agoHelpfull: Yes(8) No(3)
• maximum possibility is 4.....
  so the answer is 6.
• 13 years agoHelpfull: Yes(7) No(10)
• how msny ways they can sit...mean simple, there r 4 chair...
  1st tabl 4 pepl...2nd 3 ppl...3rd tabl 2 ppl...4th 1 ppl.... so
  
  4ways
• 13 years agoHelpfull: Yes(6) No(16)
• 10c4 that is 210 ways
• 13 years agoHelpfull: Yes(6) No(26)
• no of people can be sited in one table in 4! ways...
  so to be sit in 10 tables (4!)^10
• 13 years agoHelpfull: Yes(4) No(10)
• there is 10members.
  so there is 2 way that they will sit in the library without blank chair.
  ans is 2.
• 13 years agoHelpfull: Yes(4) No(4)
• Since no chair has to b left blank,no of ppl-->40.
  40 ppl to be seated around 10 tables can interchange their places around the table as well as across the table.
  Across the table-(as the ppl have to be arranged and not selected, permutation should be used): 40 P 10
  Around the table-4!
  Ans: 40P10*4!
• 13 years agoHelpfull: Yes(4) No(4)
• THE question is right but maybe not answers
  becoz 4,3,2,1 can be placed but to get all ways of doing this we have to get value of 10c4 and then arrange all of them
• 10 years agoHelpfull: Yes(4) No(0)
• 7 distinct values is 381
• 8 years agoHelpfull: Yes(0) No(0)