A circular dashboard of radius 1.0 ft is at the distance of 20 ft from you. you throw a dart at it and it hits the dashboard at some point Q in the circle. what is the prob that Q is closer to the center of the circle thatn periphery?

• Forget the 20 feet distance and the 1 ft radius.
  Let radius= 2r
  As a guide draw a random radius(2r) circle.
  Inside it draw a circle of radius r, i.e. of half the radius.
  Clearly Q is closer to center if it lies inside the smaller circle.
  If E is the event of hitting a point closer to the center,
  P(E)= P(hitting inner circle)/P(hitting anywhere in the whole dashboard)
  P(E)= Area of inner circle/Area of dashboard
  P(E)= pi*r*r/pi*2r*2r = 1/4 or 0.25
• 11 years agoHelpfull: Yes(7) No(1)
• if q is closer to the circle..than the perphery then it will lie within the 1,2 feet radius..
  so probability =favourable cases/total cases
  
  in this area it s nt the cases it is the are
  so area of a circle is directlt propotional to r^2
  so p=(1/2)^2 /(1)= 1/4=0.25
• 13 years agoHelpfull: Yes(4) No(7)
• to hav q clser to cntr dist of q frm cntr shld be < 0.5 ...
  so divide d circle into 16 parts each havng 1/16 prob ..
  hence der r 4 parts whch r closer to cntr..
  so total prob is 4*(1/16)=0.25
• 13 years agoHelpfull: Yes(1) No(2)
• .25 ll b ans
• 13 years agoHelpfull: Yes(1) No(1)