how many 3-digit numbers can be formed from the digits 2,3,5,6,7 and 9 which are divisible by 5 and none of the digit is repeated.

5
10
15
20

• Ans:20 the key word here is divisible by 5 hence in units place we have to fill 5
  oly which is divisible by 5.(1 way)..tens place we have a choice to fill among 5 numbers(5 ways)..and last in hundredth place we have to choose among any four number (4 ways) hence..(5*4*1)=20
• 11 years agoHelpfull: Yes(9) No(2)
• 5*4*1=20
• 11 years agoHelpfull: Yes(5) No(0)
• any 3 digit number formed from given digits to be divisible by 5 the unit digit must be 5.so unit digit can take only one number and digit at ten's place can be filled by 5ways nd similarly..digit at hundred's position can be filled by (5-1=4)numbers..
  total 3 digit number divisible by 5 frome given digits =5*4*1=20
• 11 years agoHelpfull: Yes(2) No(0)
• ans -20
  as unit place is occupied by 5 only and tens and hundred place are occupied as 4*5
• 11 years agoHelpfull: Yes(1) No(0)
• @shoaib pls expln the ans
• 11 years agoHelpfull: Yes(0) No(2)
• last dgt is fixed..so 5*4=20
• 11 years agoHelpfull: Yes(0) No(0)
• ans will be 5p2=20.
• 11 years agoHelpfull: Yes(0) No(0)
• 20 since 5 is fixed reamining is 5*4
• 11 years agoHelpfull: Yes(0) No(0)
• the last digit should be multiple of 5
  so we can arrange in 1 way
  the 2nd digit can be arranged in remaining 5ways
  and 1st digit in 4 ways
  so 5*4*1=20ways
• 11 years agoHelpfull: Yes(0) No(0)
• 20
  as the number should be divisible by 5,so the unit digit must be 5.After that for ten's place we have 5 ways and for hundred's place we have 4 ways.so the total no.of ways=5*4=20 (if the digits is not repeated)
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• Since it is 3 digit divisible by 5
  
  so unit digit we can fill by one way
  tens place we can fill by 4 ways.
  hundreds place we can fill by 5 ways.
  
  total no of ways is (5*4*1)=20
• 9 years agoHelpfull: Yes(0) No(0)