a die is rolled and a coin is tossed .find the probability that the die shows an odd number and the coin shows a head.
option
a) 1/4
b) 1/2
c) 3/4
d) 2/3

• ans:1/4
  becoz,probability that the die shows an odd number is (1,3,5)hence 3/6 ie)1/2
  probability that the coin shows a head is(1) hence 1/2 so 1/2*1/2=1/4
• 10 years agoHelpfull: Yes(12) No(4)
• 1/2*1/2=1/4
• 10 years agoHelpfull: Yes(5) No(1)
• sample space (1,h),(1,t),(2,h)(2,t).............(6,h)(6,t)
  Favorable =(1,h),(3,h),(5,h)
  Probability= 3/12=1/4
• 10 years agoHelpfull: Yes(3) No(0)
• p(head)= 1/2
  p(odd)=3/6
  so the total probability is 1/2*1/2=1/4
  
  
• 10 years agoHelpfull: Yes(2) No(4)
• ans:1/4
  
  =1/2*1/2
  
• 10 years agoHelpfull: Yes(2) No(0)
• sample space ={(h,1),(h,2)...,(h,6),(t,1)...,(t,6)} , which is 12 in number
  according to the condition , only coin with head and dice with odd number is include...i.e 3
  so p=1/4
• 8 years agoHelpfull: Yes(2) No(0)
• two events occur simultaneously so (1/6*1/2)+(1/6*1/2)+(1/6*1/2)=> 1/12+1/12+1/12 => 3/12 =>1/4 ans. is (A) 1/6 probability for one odd no. and 1/2 for head and 3 cases for odd no. i.e. 1,3,5, with each have two cases head or tail
  
  
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(1) No(1)
• correct answer will be 3/4
  
  Reason - probability of head is p(head) = 1/2
  
  probability of odd number is p(odd) = 3/6 which is equal to 1/2 (as only three
  
  odd number are there in one die)
  
  Therefore p(head) & p(odd) = 1 - [p(head)*p(odd)] = 1 - 1/2*1/2 = 1 - 1/4
  
  which is equal to 3/4 .
• 10 years agoHelpfull: Yes(0) No(36)