It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a men exceed that of a women?

• 6 times
  If 9 women,1 day work= 1/x ---(i)
  So 3 men, 1 day work=1/(x-5) ---(ii)
  Also given 3 women and 2 men 1 day work= 1/6 ---(iii)
  From (i),3 women 1 day work=1/3x
  From (ii,2 men 1 day work=2/[3(x-5)]
  So (iii) can be represented as, 1/3x + 2/[3(x-5)]= 1/6
  Solving x=10
  So 1 woman 1 day work=1/(9*10)= 1/90 and
  1 man 1 day work=1/3(10-5)= 1/15
  Output of a men exceed that of a women = (1/15)/(1/90)= 6 times
  
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