TCS
Company
Bhaskar and Kiran start simultaneously towards each other from two different towns P and Q, which are 100 km apart, with speeds of 20 kmph and 50 kmph respectively. After reaching their destinations, they turn back to their respective starting stations. At what distance from Q does Kiran cross Bhaskar for the second time?
option
a) 40 km
b) 331/3 km
c) 60 km
d) 662/3 km
Read Solution (Total 7)
-
- answer of the above question is none of them.....
let P-------------Q now bhaskar has speed of 20 km/p so it takes 5h to reach Q from p for bhskar but the speed of kiran is 50 km/p so he takes only 2h to reach p from q....when kiran is on p,at that time bhaskar is only 40 km from p and walking towards q....now for the second time, let at a distance of x km from P they meet thereore...kiran has to cover whole x km in the same time as bhaskar covers x-40 km...now...(x-40)/20 =x/50.....gives x=200/3 km from P...therefore distance from Q is 100-x= 100-200/3 = 100/3 = 33.33 km - 11 years agoHelpfull: Yes(8) No(0)
- @tanu please yar update the correct ans with ur question..
- 11 years agoHelpfull: Yes(2) No(0)
- @tanu plz tell the correct option
- 11 years agoHelpfull: Yes(2) No(0)
- Time taken by Kiran to reach P= 2hrs
=>Distance covered by bhaskar in 2 hrs= 40kms
Now appliying relative motion concept
Kiran has to cover 40 kms with speed of (50-20)km/hr=30 km/hr( because both are moving in same direction)
=> Distance to be covered = 40kms
Speed = 30 km/hr
=>time taken =40/30 hrs=1.33hrs
Total distance covered by bikram in this time at 20 km/hr=40kms+20*1.33kms
=66.66kms
=> distance from point q =100-66.66 = 33.33kms - 11 years agoHelpfull: Yes(2) No(0)
- @Pramod Actually one of the option is correct.
- 11 years agoHelpfull: Yes(1) No(1)
- pramod is right 33.33
- 11 years agoHelpfull: Yes(0) No(0)
- (b) is the correct option
- 11 years agoHelpfull: Yes(0) No(4)
TCS Other Question