the number of bacteria in a colony was growing exponentially.at 4 pm yesterday the number of bacteria was 400 and at 6 pm it was 3600.how many bacteria were there in the colony at 7pm?

• 400*3=1200 at 5pm
  1200*3=3600 at 6pm
  
  so 3600*3=10800
• 13 years agoHelpfull: Yes(63) No(2)
• let at 5pm the bacteria were x. so, according to GP -- x/400 = 3600/x
  that is, x^2 = (3600)(400). therefore, x = 1200.thus the factor with which the bacterias are increasing is 3. therefore, the number of bacteria at 7pm will be 3600 x 3 = 10800
  
• 13 years agoHelpfull: Yes(37) No(2)
• We Have D Formula 4Population growth as:
  
  P(final) = P(initial) {1 + r/100}^n
  
  Substitute D given values 2evaluate..!!
  
  Ans: 10800
• 13 years agoHelpfull: Yes(24) No(6)
• 10800
  4pm->400,5pm->400*3=1200,6pm->1200*3=3600,7pm->3600*3=10800
• 13 years agoHelpfull: Yes(15) No(0)