One train leaves Los Angeles at 15mph heading for New York. Another train leaves from New York at 20mph heading for Los Angeles on the same track. If a bird, flying at 25mph, leaves from Los Angeles at the same time as the train and flies back and forth between the two trains until they collide, how far will the bird have traveled?

• let they meet after t time then
  distance travel by 1 rain = 15t
  distance travel by another train=20 t
  so total distance b/w two station = 15t +20 t=35t
  so t= distance b/w station / 35
  distance travel by flies = t *25=distance b/w station *25/35
  
• 13 years agoHelpfull: Yes(10) No(3)
• It will depend on distance between New york and los Angles.
  If s miles is the distance, then bird would have traveled s*25/35 miles.
• 14 years agoHelpfull: Yes(3) No(2)
• 125 miles
  we need to find out the distance at which all three bodies will coincide..
• 13 years agoHelpfull: Yes(1) No(2)
• ans : well its coming out approx .76x where x is distance between the stations, dont ask me how its a very complex series.
  
  S = 25x/45 + 25/40(25x/45-15/45x) + 25/45( 25/40(25x/40-15x/45) - (20/40(25/40
  (25x/45-15/45))) + ..........
  
  
• 14 years agoHelpfull: Yes(0) No(1)
• It travels 15*H miles if the trains colloid after H hours
  Since the bird flies back and forth the bird will roam there only
• 13 years agoHelpfull: Yes(0) No(0)
• The bird will have travelled the distance between Los Angeles and New York.
  
  As the bird will move to and fro over trains, these trains moving towards each other will have covered the distance between Los Angeles and New York.
  
  
• 13 years agoHelpfull: Yes(0) No(0)
• no need of distance here...if a train travels with 15mph and b train travels with 20mph. then at 3/4th hr they'll collide,since the bird travells 25mph,so at 3/4hr it has travelled 25*3/4=17.5mph
• 11 years agoHelpfull: Yes(0) No(1)