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Logical Reasoning
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in an examination 70% of the candidates passed in history and 50% in geography and 20% failed in both the subjects.if 500 students passed in both the subjects,then how many candidates appeared for the exam?
Read Solution (Total 7)
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- no. of students passed in geography and history=(100-20)=80%
so,{(hist) U (geo)}=(hist)+(geo)-(hist&geo)
=70+50-80
=40
a/c,40%=500
therefore 100%=(500*100)/40
=1250
so,ans is 1250 - 11 years agoHelpfull: Yes(51) No(3)
- ans=1250
let total student=x,then
x-0.2x=0.7x+0.5x-500,
x=1250 - 11 years agoHelpfull: Yes(39) No(3)
- x=70x/100 +50x/100-500
x=140x-50000/100
x=1250
- 11 years agoHelpfull: Yes(7) No(9)
- 1250
using formula,
P(AorB)= P(A)+ P(B)- P(A&B) - 11 years agoHelpfull: Yes(4) No(1)
- it is given that 20% student failed in both the subject it means that 80% student passed in both subjects and 500 student passed in both subjects.
80% of total no of students=500
hence total no of student is 625.
Ans is 625 - 11 years agoHelpfull: Yes(4) No(19)
- because P(A)=7/10 P(B)=5/10 P(AuB)=1-(2/10)=8/10
THEREFORE P(A&B)=P(A)+P(B)-P(AUB)=4/10
Because 40% of x=500(given)
so x=1250 which is the total no of candidates appeared. - 11 years agoHelpfull: Yes(3) No(2)
- A=History,B=Geography
no of students passed in A and B =(100%-20%)=80%
N(A)=70,N(B)=50,N(AuB)=80%
so,
N(AUB)=N(A)+N(B)-N(AUB)
=70%+50%-80%
=120%-80%
=40%(500),20%(250)
THEREFORE 100%=(40%*2=80%(1000)+20%(250))
SO,ANS IS =100%(1250) - 11 years agoHelpfull: Yes(2) No(1)
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