a tourist wants to visit 3 or more of the 5 major cities in india mumbai, bengaluru, chennai, delhi, Kolkata. In how many ways can he plan his tour such that Chennai is always included? The plan of the Tour are different if the cities in the tour or the order of cities is different?

• 4C2*3! + 4C3*4! + 4C4*5! = 252
• 10 years agoHelpfull: Yes(87) No(9)
• we have to exclude 1 city i.e chennai. so from the remaining four we can select 2,3,4 cities bcoz we hv to select >=3 city.the first term is 4c2*2!(2! bcoz of 2 city's own arrangement) second term- 4c3*3! third term- 4c4*4!
  adding these we get 12+24+24=60 (ans)
• 10 years agoHelpfull: Yes(17) No(13)
• 4c2*2!+4c3*3!+4c4*4!=60
• 10 years agoHelpfull: Yes(11) No(15)
• 3!*4c2 + 4!*4c3 + 5!*4c4 = 252
• 10 years agoHelpfull: Yes(6) No(1)
• 1*4*3+1*4*3*2+1*4*3*2*1=60
• 10 years agoHelpfull: Yes(2) No(4)
• For Visit to 3 cities 1 of which is Chennai - 1*4*3 and since the plan of tour is different if the order of cities is different-(1*4*3)*3!=96. Similarly (1*4*3*2)*4!=576 and (1*4*3*2*1)*5!=2880. Total=3552
• 10 years agoHelpfull: Yes(2) No(4)
• a)5(4!+3!+2!)
  b)5!+4*4!+6*3! =====(252)
  c)5!+4!+3!
  d)5C5+4C3+4C2
  
  As chennai is always there , so tourist have to choose 2 cities out of 4 cities(excluding chennai)....and this can be done by
  Chennai must always be includes.
  for 3 cities 4C2*3!=====6*3!===36
  for 4 cities 4C3*4!=====4*4!===96
  for 5 cities 4C4*5!=====1*5!===120
  total =========5!+4*4!+6*3!====120+96+36======252
  
  
• 7 years agoHelpfull: Yes(1) No(0)
• can any one please send me 2014 tcs recent paper to my mail,20th sep i have tcs campus at vizag..............
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• 10 years agoHelpfull: Yes(0) No(7)
• 1*4c2+1*4c3+1*4c4=11
• 10 years agoHelpfull: Yes(0) No(4)
• 20
  using permutation
  5P3
• 10 years agoHelpfull: Yes(0) No(3)
• please send me all TCS 2014 placement papers to abhir95@gmail.com. i have my campus placement in next 5 days..
• 10 years agoHelpfull: Yes(0) No(2)
• 36.there are 5 choices,one is taken by chennai,so other 2 are 4*3=12.and there are
  3 such orders.so 3*12=36.
• 10 years agoHelpfull: Yes(0) No(2)
• 4c2*2!+4c3*3!+4c4*4!=60
• 10 years agoHelpfull: Yes(0) No(4)
• tourist can go to either 3,4,5 cities.So for 3 cities permutataion will me (4c1*3c1)*3!=72.Now, for 4 cities (4c1*3c1*2c1)*4!=576, for 5 cities (4c1*3c1*2c1*1c1)*5!=2880.Therefor total 72+576+2880=3528.
• 10 years agoHelpfull: Yes(0) No(1)
• (4c2*3c1*1c1)+(5!)=9+120
  ans=129
• 10 years agoHelpfull: Yes(0) No(3)
• 4c3*3!+4c3*4!+5!
• 9 years agoHelpfull: Yes(0) No(1)
• Chennai must always be includes.
  for 3 cities 4C2*3!=36
  for 4 cities 4C3*4!=96
  for 5 cities 4C4*5!=120
  total 252
  
• 8 years agoHelpfull: Yes(0) No(0)