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A person has to cover the fixed distance through his horses. There are five horses in the cart. They ran at the full potential for the 24 hours continuously at constant speed and then two of the horses ran away to some other direction. So he reached the destination 48 hours behind the schedule. If the five horses would have run 50 miles more, then the person would have been only 24 hours late. Find the distance of the destination.

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Suppose his actual speed is 'v' with 5 horses,
If he travelled that 50 miles with 5 horses the time taken wud b 50/v, which equals time taken with 3/5th speed minus 24hrs

50/v = 50/(3v/5) - 24;
so, v = 25/18;

Now, suppose after 1st 24 hrs he takes 't' hrs toreach his destination, then

vt = (3v/5)(t + 48);
vt = (3v/5)(t+48)
t = 72

total time = 72+24 = 96

distance = 400/3
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