2 years ago of A is x times that of B. 3 Years hence the age of A is 4/3 times of B. What is the present age of B in binary form?

• let age of A be a and age of B be b.
  a-2=x*b--1st eq.
  a+3=4/3b--2nd eq.
  so (2nd eq)-(1st eq):
  5=(4/3-x)*b---3rd eq.
  here we can see that 5 is a prime no.
  so b shud be 5 becoz if we will take (4/3-x)=5 then x will be negative which is not possible.
  so b=5yrs.
  x=1/3
  a=11/3 yrs.
  now changing 5 in binary it will be 101.
  so age of b in binary is 101.
• 12 years agoHelpfull: Yes(16) No(1)
• x would be supplied
  
  2 years ago A=xB----(1)
  after 5 years(2+3) age will be
  => 5+A=4/3(xB+5)------(2)
  we substitute A in eq2
  =>15+3xB=4xB+20
  =>xB=5
  =>B=5/x
  
  Binary value of 5/x is the ans
• 12 years agoHelpfull: Yes(8) No(10)
• A-2=XB-->1,
  3+A=4/3B-->2,
  slove 2eq,
  get A=4B-9/3
  sub.to 1eq,
  got B=15
  binary form=1111
• 12 years agoHelpfull: Yes(2) No(12)