N is an integer and N 2 at most how many integers among N 2 N 3 N 4 N

Ans = 2
Because max. no. of prime integer was asked.
Let N=4
4+2=6
4+3=7 prime
4+4=8
4+5=9
4+6=10
4+7=11 prime

try with n=5,6,7,8 etc
11 years agoHelpfull: Yes(3) No(0)
2 bcoz, for any value of N only 2 prime num's will be there for given series
11 years agoHelpfull: Yes(2) No(2)
2. check with any possible integer
11 years agoHelpfull: Yes(1) No(0)
Guys the Ans is 3 put n=105, we get 107, 108,109,110,111,112 out of these 107,109,111 are prime nos
11 years agoHelpfull: Yes(1) No(16)
consider n=3
n+2=5, n+3=6, n+4=7, n+5=8, n+6=9, n+7=10
among them only 2 are prime
11 years agoHelpfull: Yes(1) No(0)
2 is the right ans becoz by checking with any n>2 integer, 2 numbers are always get prime in between consecutive 6 nos..
11 years agoHelpfull: Yes(0) No(0)
3.prime numbers are always odd except 2.here n>2,so answer is 3.7+6=13,a prime no.
11 years agoHelpfull: Yes(0) No(2)
1 check with n=19 or n=20
11 years agoHelpfull: Yes(0) No(1)
max of 2 int are possible bcoz...with the units digit as 2,4,5,6,8,0 can never b prime,so only 1,3,7,9 are left,and they have a difference of 2 or 4 between each of them ,so in a set of 6 continuous numbers there can b at most 2 primes.
11 years agoHelpfull: Yes(0) No(0)
ans is 2 by checking with n=3,4,5,6...
11 years agoHelpfull: Yes(0) No(0)

N is an integer and N>2 at most how many integers among N+2, N+3, N+4, N+5, N+6 and N+7 are prime integers.