a multiple choice question has 4 options . choosing the correct option earns the student three marks. However choosing the wrong option incurs negative marks, that if a student chooses an option randomly his expected score is zero.Suppose a student has successfully eliminated 2 incorrect options. His expected score if he chooses randomly among the remaining options is: a) 1 b)1.5 c)0 d)3

• this might make u laugh:
  in the question it clearly says that if option is chosen randomly,then the score is 0.
  so if he chooses randomly from the remaining 2 options,his score is 0.
  
• 13 years agoHelpfull: Yes(62) No(14)
• here answer will be 1.
  because first the negative marks to be calculated=3x1/4+X(let)x1/4=0(given)
  gives X=-1.this is negative marks.
  thean,after elimination,E(X)=3x1/2+(-1)x1/2=1
• 13 years agoHelpfull: Yes(31) No(7)
• ans will be 3..becoz if he chooses write option then he will get 3
  and if he chooses wrong option he will get -ve marks...so option D
• 13 years agoHelpfull: Yes(9) No(6)
• His expected score can never be 0 because if he select correct option then he will get 3 marks otherwise, he will get marks in negative.
• 13 years agoHelpfull: Yes(7) No(12)
• if he select one answer from 4 options expected score is 0....if he eleminiate 2 options frm 4 options exepected score is 1.5.....
• 13 years agoHelpfull: Yes(4) No(11)
• there is same(1/2) chances that the student choose write ans and wrong ans.
  a.) so total chances that he can score 3 is (3*(1/2)).
  b.) chances that he score negative is ((1/3)*(1/2)).
  so total chances=a+b
  its something around 1.66
  so,ans is 1.5
• 12 years agoHelpfull: Yes(4) No(3)
• 3
  if he chooses the wrong answer his mark should be 2 but there is no option with answer 2
• 12 years agoHelpfull: Yes(1) No(5)