TCS
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Numerical Ability
Permutation and Combination
A girl has to make pizza with different toppings. There are 8 different toppings. In how many way can she make pizzas with 2 different toppings?
a)16 b)56 c)112 d)28
Read Solution (Total 22)
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- it can be done in 8c2 ways=28
ans:28 - 13 years agoHelpfull: Yes(71) No(20)
- Considering First Toplling...Possible Pairs Are (1,2)(1,3)....(1,8) Total 7...Consider 2nd Toppling (2,1)(2,3)...(2,8) Like These All Comes To 7*8=56
- 13 years agoHelpfull: Yes(24) No(57)
- 8c2 = 8*7/2 = 28
- 13 years agoHelpfull: Yes(22) No(6)
- ofcourse 8c2 i.e. 28 ways...
many people saying 56 by defining combination like
(1,2)(1,3)....(1,8) Total 7...Consider 2nd Toppling (2,1)(2,3)...(2,8) Like These All Comes To 7*8=56 but,
(1,2) and (2,1) is same combination guys so its wrong... - 11 years agoHelpfull: Yes(18) No(0)
- 8C2, use combination
- 13 years agoHelpfull: Yes(14) No(5)
- 8c2=8*7*6!/2!*6!=28
- 13 years agoHelpfull: Yes(13) No(3)
- 8c2=8*7/2=28
- 13 years agoHelpfull: Yes(11) No(3)
- 8c2=56 is the answer
- 13 years agoHelpfull: Yes(10) No(81)
- total 8 different toppings are there,she makes 2 different toppings
8c2=28 - 13 years agoHelpfull: Yes(9) No(3)
- 8c2 ways nothing but 8*7/2*1=28 ways
- 13 years agoHelpfull: Yes(7) No(4)
- 8p2=28...tats right answer...
- 12 years agoHelpfull: Yes(4) No(9)
- its is about arranging 2 different toppings .. and so it shuld be 8P2. which is equal to 57 arrangements can be done.... use permutation....
- 12 years agoHelpfull: Yes(3) No(3)
- (1,2)(1,3)(1,4)(1,5)(1,6)(1,7)(1,8)--taking with 1 and repeating with others
(2,3)(2,4)(2,5)(2,6)(2,7)(2,8)
(3,4)(3,5)(3,6)(3,7)(3,8)
(4,5)(4,6)(4,7)(4,8)
(5,6)(5,7)(5,8)
(6,7)(6,8)
(7,8)--ans 28 - 8 years agoHelpfull: Yes(2) No(0)
- 8 fro 2 choice 8c2 =28
- 9 years agoHelpfull: Yes(1) No(0)
- it would be 8^2-8=56
- 9 years agoHelpfull: Yes(1) No(1)
- 56
coz 7* 8=56 - 8 years agoHelpfull: Yes(1) No(1)
- yeah,28 ways,by using combination 8c2=8!/2!*6!
- 8 years agoHelpfull: Yes(1) No(0)
- ofcourse 8c2 i.e. 28 ways...
- 10 years agoHelpfull: Yes(0) No(0)
- it can be done in 8c2 ways and answer is 28
- 8 years agoHelpfull: Yes(0) No(1)
- We need to select two topping from 8 toppings.So this problem is upon combination.
This can be done in 8c2 ways.
(8*7)/2=28 - 6 years agoHelpfull: Yes(0) No(0)
- Formula nCr= nC n-r
8C2=8C(8-2)
8C6=8*7*6/6 = 56 - 5 years agoHelpfull: Yes(0) No(1)
- The answer is 8C2=28
- 4 years agoHelpfull: Yes(0) No(0)
TCS Other Question
Alice & Bob play the following chip-off-game. Given a pile of 122 chips, Alice 1st picks at least one chip but not all chips. In subsequent turn a player picks at least one chip but no more than the number picked on the previous turn by the opponent. the player to pick the last chip wins. which of the following is true?
1)in order to win alice should pick up two chips on her 1st turn
2) in order to win, alice should pick 30 chips on her 1st turn
3) in order to win, alice should pick 1 chip on her 1st turn
4) alice has no winning strategy
On average age something like a, b, c weigheted separately 1st a, b, c, then a & b, then b & c , then c 7 a at last abc, then last weight was 167, then what will be the avg weight of the 7 weight?