On average age something like a, b, c weigheted separately 1st a, b, c, then a & b, then b & c , then c 7 a at last abc, then last weight was 167, then what will be the avg weight of the 7 weight?

• in this a+b+c=167
  n we have to find (a+b+c+a+b+a+c+b+c+a+b+c)/7
  the above equation can be written as (4a+4b+4c)/7=4(a+b+c)/7
  so the answer is 4*167/7=95.42
• 13 years agoHelpfull: Yes(9) No(0)
• there are 7 weights
  a
  b
  c
  a+b
  b+c
  c+a
  and finally a+b+c.
  given that a+b+c = 167
  we require average of above 7 weights. so it becomes (4(a+b+c)/7)= 4*167/7 = 54.53
  ans: 54.53
• 13 years agoHelpfull: Yes(1) No(5)
• here imp is abc means sum of weibht of 3 persons a,b,c. therefore, abc=a+b+c=167, now apply average formula
  a+b+c+ab+bc+ca+abc/7=4(a+b+c)/7=4*167/7=ans
• 13 years agoHelpfull: Yes(0) No(1)