TCS
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Numerical Ability
LCM and HCF
2 gears one with 12 teeth and other one with 14 teeth are engaged with each other. One teeth in smaller and one tooth in bigger are marked and initially those 2 marked teeth are in contact with each other. After how many rotations of the smaller gear with the marked teeth in the other gear will again come into contact for the first time?
a) 7
b) 12
c) Data insufficient
d) 84
Read Solution (Total 5)
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- lcm(12&14)=84
since the biger gear rotates 84 teeth in 6 rotations
and smaller gear rotates 84 teeh in 7 rotations
Ans-a) - 10 years agoHelpfull: Yes(31) No(2)
- i think its lcm of 12 and 14 ie 84
- 10 years agoHelpfull: Yes(22) No(14)
- Correct Option : A
Assume the distance between the teeth is 1 cm. Then the circumference of first gear is 12 cm and the second is 14 cm.
Now LCM (12, 14) = 84. So to cover 84 cm, the first gear has to rotate 8412 = 7 rounds (the second gear rotates 84 / 14 = 6 rounds as it is bigger)
- 10 years agoHelpfull: Yes(7) No(0)
- 84(LCM OF 12 AND 14)
- 10 years agoHelpfull: Yes(3) No(4)
- @ash Which is the correct ans???
- 10 years agoHelpfull: Yes(2) No(3)
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