circle has 2 chords one of length 6 cm and other of length 8 cm.distance between them 1.. find diameter.

• Chord length = 2 $sqrt{r^2 - d^2}$
  
  = 2 $sqrt{8^2 - 6^2}$
  
  = 2 $sqrt{64 - 36}$
  
  = 2 $sqrt{28}$
  
  = 2 X 5.29
  
  = 10.58 cm
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• 10 cm.................................................................
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• Let x be the distance the 8cm chord and the centre.
  then
  distance between chord and centre=sqrt(radius^2-(chord length/2)^2)
  x=sqrt(r^2-(8/2)^2)
  x^2=r^2-16;
  
  r^2=x^2+16;
  
  x+1 is the distance between 6cm chord and centre
  (x+1)^2=(r^2-(6/2)^2)
  (x+1)^2=r^2-9;
  from above eqn,
  x^2+2x+1=x^2+16-9
  2x+1=7
  2x=6
  x=3;
  sub in first eqn
  x^2+16=r^2
  r^2=25
  r=5
  therefore d=10
  
• 9 years agoHelpfull: Yes(0) No(1)