given a square of length oh 2m. its corners are cut such that to represent a regular octogon.find the length of side of octogon

• each corner cut is an isosceles triangle(45-90-45)so if its hypotenuse(side of octagon) is 'a' then each side of the triangle is 'a/√2'
  therefore: (a/√2)+a+(a/√2)=2
  solving we get a=0.828m
• 11 years agoHelpfull: Yes(30) No(1)
• =2√2/(2+√2)
  
• 11 years agoHelpfull: Yes(10) No(0)
• let the side of octogon be a. then the side of square in terms of 'a' is a(1+root 2)
  then a(1+root2)=2
  by solving a=2/(1+root2)
• 11 years agoHelpfull: Yes(9) No(1)
• 1 because for octagon 8 sides will be there so each represents 1cm
• 11 years agoHelpfull: Yes(4) No(9)
• 2/(root2+1)
• 11 years agoHelpfull: Yes(4) No(0)
• 2-sqrt(2)
  
  x^2 + x^2=(2-2x)^2
• 11 years agoHelpfull: Yes(3) No(2)
• let x part of squire is cut
  then length of octagon=2-2*x
  also x^2+x^2=2-2*x
  x=2*(2)^1/2/(1+2^1/2)
• 11 years agoHelpfull: Yes(2) No(0)
• ans is 2/root(2)+1
• 11 years agoHelpfull: Yes(2) No(0)
• use pythagorus theorem to get x=2/(2+root2)
• 11 years agoHelpfull: Yes(1) No(0)
• let side of octogon be x
  by pythagoras theorem,
  x^2=(1-.5x)^2+(1-.5x)^2
  x=.667 m
• 11 years agoHelpfull: Yes(0) No(3)
• 2.414 from pythagoras theoram sqrt(2)=sqrt(L/2)-sqrt(2)
• 11 years agoHelpfull: Yes(0) No(1)
• reg hexagon of 2sqrt(2)/(2+sqrt(2))
• 11 years agoHelpfull: Yes(0) No(0)
• Sol:
  
  Let x is the side of the octagon and x + 2y is the side of the square.
  In the given octagon, y2+y2=x2⇒2y2=x2⇒y=x2√
  But x2√+x+x2√=2
  ⇒2√x+x=2
  ⇒x=22√+1=22√+1×2√−12√−1=2(2√−1)
  
• 9 years agoHelpfull: Yes(0) No(0)