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Numerical Ability
Probability
There are 7 children and the youngest child is a boy.What is the probability that all of them are boys ?
Read Solution (Total 6)
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- 1/64
given youngest is boy
remaining 6 children
so for one child probablity of boy=1/2
for six it will be=1/2*1/2*1/2*.....6times=1/64 - 13 years agoHelpfull: Yes(13) No(2)
- 1/64.s'odiafjksdmclknxoifjcl mc;kmpdk c
- 13 years agoHelpfull: Yes(2) No(5)
- 1/2*1/2*1/2*1/2*1/2*1/2=1/64
- 13 years agoHelpfull: Yes(2) No(0)
- 31 can be distributed as=>
16+8+4+2+1=31 - 13 years agoHelpfull: Yes(1) No(8)
- the answer is 1/64. the first six could either be boy or girl so there are 2^6 probabilities
- 13 years agoHelpfull: Yes(1) No(0)
- youngest childm is=1/2
six digit=1/2*1/2*1/2*1/2*1/2*1/2
ans =1/64 - 8 years agoHelpfull: Yes(0) No(0)
TCS Other Question
21 people meet and shake hands. The maximum number of handshakes possible if there is no cycle of handshakes is
(A cycle of handshakes is a sequence of people a1, a2,.... ,ak such that the pairs (a1, a2), (a2, a3), (a(k-1), ak), (ak, a1) shake hands.
a) 17 b) 18 c) 19 d) 20
Entry ticket to an exhibition ranges from 1p to 31p. You need to provide exact change at the counter. You have 1p coin. In how many parts will you divide 31p so that you will provide the exact change required and carry as less coins as possible.