Entry ticket to an exhibition ranges from 1p to 31p. You need to provide exact change at the counter. You have 1p coin. In how many parts will you divide 31p so that you will provide the exact change required and carry as less coins as possible.

• Answer is 5.
  16 8 4 2 1 which makes a total of 31.
• 13 years agoHelpfull: Yes(55) No(12)
• in 5 parts
  i.e. 1, 2, 4, 8, 16 paise he should have
• 13 years agoHelpfull: Yes(11) No(2)
• 2^0,2^1,2^2,2^3,2^4=5
• 13 years agoHelpfull: Yes(10) No(5)
• ans is 5
  1 2 4 8 16 32
• 13 years agoHelpfull: Yes(7) No(15)
• 4 parts of coin as 3*10 and 1 paise coin
• 13 years agoHelpfull: Yes(6) No(27)
• only 3 coins needed 1*20P + 1*10P+ 1*1P=31P
• 9 years agoHelpfull: Yes(1) No(0)
• As per the que, ticket ranges from 1p to 31p so it can be 7p or 13p or 31p etc.
  If we keep 1p coins in a set of 1coin,2coins,4coins,8coins & 16 coins we can easily provide the amount.
  Let d price of ticket is
  13p=8+4+1
  24p=16+8
  Etc etc.
  So Answer is 5.
• 8 years agoHelpfull: Yes(0) No(0)