At 6.00 a.m Divya starts to walk from her house at 5kms an hour. At 8.30 a.m, Preetha follows her from Divya's house on her bicycle at 8 kms per hour. When will divya be 1 km behind Preetha?
option
a) 12.00 p.m
b) 1.00 p.m
c) 1.30 p.m
d) 2.30 p.m

• i think answer is 1pm.
• 10 years agoHelpfull: Yes(16) No(1)
• relative speed=3km/hr
  distance to cover is 12.5+1 km=13.5km
  time req=4.5 hr
  so 8.30+4.5=1pm
• 10 years agoHelpfull: Yes(11) No(0)
• effective speed is 3km/hr....now distance b/w them is 12.5
  to cover 11.5 km at 3km/hr...it takes 3hrs and 50 mins...
  so from 8.30 the tym will be 12.20 pm....
  but not given in options
• 10 years agoHelpfull: Yes(4) No(5)
• by 830 distance bw them=12.5kms
  hence to cover 11.5 km @relative speed of 3km/hr she needs 3.5hrs hence 12:00noon
• 10 years agoHelpfull: Yes(2) No(10)
• 13.5 km = 3*t
  => t=4.5 hrs
  now adding 4.5 hrs to 8.30 we get 1 pm
  
• 10 years agoHelpfull: Yes(2) No(0)
• 1 PM IS THE CORRECT OPTION
  
• 10 years agoHelpfull: Yes(1) No(0)