Eri threw two dice and his score is the sum of the values shown .Sandy throws one die and her score is the square of the value shown. find the probability that sandy's score wil be strictly greater than eri's score?

• the maximum sum of two dice is 12 i.e Eri's maximum value is 12.
  now,if Sandy get more than 12 then her value will be strictally greater than Eri.
  so, the only square of 4,5,6, is greater than 12..
  probability=3/6=>1/2
• 10 years agoHelpfull: Yes(31) No(11)
• Sandy may score 1,4,9,16,25 or 36 that is square of all the possibilities of one dice thrown by sandy.
  Eri's total possibilities = 36 for two dice
  sum of two dice may be 2,3........,12
  
  according to question Sandy's score strictly greater than Eri's so
  
  for Sandy's 1 there is no any possibilities to get greater
  for 4 Eri's possiblities {(1,1),(1,2),(2,1)}=3
  for 9 Eri's possiblities i.e. sum less than 9= {(1,1),.....(1,6),(2,1)......(2,6),(3,1)....(3,5),(4,1)....(4,4),(5,1)....(5,3),(6,1),(6,2)}=26
  for 16 Eri's possibilities all combination (because maximum sum=12 of two dice)=36
  for 25 Eri's possibilities =36
  for 36 Eri's possibilities= 36
  
  so total no of favorable cases=3+26+36+36+36=137
  and total no. of sample space=6*6*6=216
  so,
  probablitiy=137/216
  
• 10 years agoHelpfull: Yes(27) No(14)
• possibilities for sandy's score greater than Eric is {(4,4),(5,5),(6,6)}
  so probability will be 3/36=1/12
• 10 years agoHelpfull: Yes(8) No(16)
• if sandy score is 1-1^2=1 eri score=0
  if 2-2^2=4 =3
  if 3-3^3=9 =17
  if 4-4^2=16,5^2=25,6^2=36 eri score may be 3*36=108
  so total values=120
  the probability may be 1/120
• 10 years agoHelpfull: Yes(1) No(4)
• as there is only one probability ie (1,1) den the sandy score is 4 so probability is 1/36.
• 10 years agoHelpfull: Yes(0) No(12)
• eri's(x+y) sandy(z^2)
  1 1 5ways(i.e 2^2=4 3^2=9 4^2=16 5^2=25 6^2=36)
  1 2 5
  1 3 4
  1 4 4
  1 5 4
  1 6 4
  2 1 4
  2 2 2
  .
  .
  .
  2 6 3ways
  3 1 4
  .
  .
  .
  .so on like this..add every one...we get total of 132
  ans=probability is (132/216=11/18)
  (dont think it is so big procedure bacause we can simply right combinations i.e for example..2 4 is 4ways
  similarly 5 1
  3 3
  4 2
  1 5
  answer will be same..so it can be written fast
  if anything wrong pls post new answer and corct me.:)
• 10 years agoHelpfull: Yes(0) No(0)
• pls send me tcs apti papers 2013.......my id-rharsh170@gmail.com
• 10 years agoHelpfull: Yes(0) No(0)