Jake is faster than Paul. Jake and Paul each walk 24 km. The sum of their speeds is 7 km/h and the sum of time taken by them is 14 hours. Then Jake's speed is equal to :

• Given that speed of Jake is greater than Paul
  Distance = 24 km
  Sum of their speed is 7 km/h = J+P
  So possible speed ratio between J & P is
  Go by Option
  6:1 Not in option
  5:2 = (24/5)+(24/2) ≠ 14 Hours
  4:3 = (24/4)+(24/3) = 14 Hours
  So Jake’s speed is 4km/h
• 10 years agoHelpfull: Yes(112) No(3)
• since distance=24 km
  let jake speed=x kmph
  paul speed=y kmph
  a/c to question
  x+y=7
  or
  y=7-x
  now,
  24/x+24/y=14
  or 24/x+24/7-x=14
  or
  1/x+1/7-x=14/24=7/12
  x+7-x/7x-x*x=7/12
  by solving
  x=3,4
  or
  y=4,3
  by using option
  4km/h
• 10 years agoHelpfull: Yes(30) No(1)
• V(p)+V(j)=7................(a)
  distance traveled by each= 24 Km
  T(j)+T(p)=14
  24/V(j)+24/V(p)=14
  1/V(j)+1/V(p)=14/24
  (V(p)+V(j))/V(p)V(j)=7/12;
  7/V(p)V(j)=7/12, from ..(a)
  V(p)V(j)=12................(b)
  
  square of (V(j)-V(p))=square of (V(j)+V(p))-4*V(p)V(j)
  by putting values from a and b
  we get,
  V(j)-V(p)=1.............(c)
  on solving a and c
  V(j)=4 Km/h
  and V(p)=3 Km/h
  
  
  
  
  
• 10 years agoHelpfull: Yes(7) No(10)
• jake's speed=x, paul's speed=y
  average speed= 2xy/x+y
  (24+24)/14=2xy/7
  xy=12
  y=12/x....1
  
  x+y=7.....2
  
  from 1 and 2 we get x=4
  x=
• 9 years agoHelpfull: Yes(5) No(0)
• given sum is 7 so one is x and other is 7-x
  so 24/x+24/7-x = 14
  check by option as
  put 4 we get 6+8 =14
  where it satisfy equation 14=14 so 4km/h ans
  
• 8 years agoHelpfull: Yes(4) No(0)
• SIMPLE LET JAKE SPEED BE 4 AND PAUL BE 3 AS SUM IS 7 AND JAKE IS FASTER THAN PAUL
  AND TIME TAKEN BY JAKE=24/4=6 AND PAUL,S TIME=24/3=8
  THEN 8+6=14
• 8 years agoHelpfull: Yes(2) No(0)
• Here it is given that
  sum of speeds V1+V2=7;------------(i)
  sum of time taken T1+T2=14--------(ii)
  Here they given jack speed is more than paul
  hence 3 cases arises it may be (v1,v2)=(6,1) or (5,2) or (4,3)
  by solving them in the equation (i) we will get v1,v2=4,3
  also it also satisfies the (ii) equation T1,T2
  v1+v2=4+3=7;
  T1+T2=6+8=14;
  hence jack speed =speed of paul+1 (V1=V2+1)
• 10 years agoHelpfull: Yes(0) No(4)
• given speed(j) + speed(paul) = 7km/hr
  
  consider speeds:- 6(4hrs) + 1(24 hrs) [28>14]
  5(almost 5hrs) + 2(12 hrs) [17>14]
  4(6 hrs) + 3(8 hrs) [14=14]
  Therefore speed of jake is equals to 4km/h
• 10 years agoHelpfull: Yes(0) No(0)
• let speed and time of Jake=x and t1 respectively
  Speed and time of Paul=y and t2 respectively(x>y.. given)so t1
• 10 years agoHelpfull: Yes(0) No(0)
• Jake = j kmph, paul = p kmph, total= j+p kmph, total time= 24/j + 24/p.. thus j+p = 7, 24/j+24/p=14.. solving we get j=4 kmph
• 8 years agoHelpfull: Yes(0) No(0)
• let the speed of jake is s1 and that of paul is s2.also time taken will be t1 and t2 respectively.
  so s1+s2=7 and t1+t2=14 also (s1>s2) solve the above conditions to find the value of s1 which is 4km/h(ans)
• 8 years agoHelpfull: Yes(0) No(0)
• Speed=j+p=7kmph
  Time =j+p=14hr
  Totally 4:3. p-4 j-3 so the ans 4kmph
• 7 years agoHelpfull: Yes(0) No(0)
• let speed of jake =x
  speed o fpaul =7-x
  total distance is 24km
  24/x +24/(7-x) =14
  solving above equation we get
  x^2-7x+12=0
  x=4,3
  jake is faster so his speed will be 4km/hr
• 7 years agoHelpfull: Yes(0) No(0)
• 4kmph
• 6 years agoHelpfull: Yes(0) No(0)
• Speed of joke =x
  Speed of paul=7-x
  Given that each walk 24km
  Tj+tp=14
  24/x + 24/(7-x) =14 after solving this eqn
  X=3,4 since joke is faster than Paul
  Speed of joke =4
• 4 years agoHelpfull: Yes(0) No(0)