One card is lost out of 52 cards. two cards are drawn randomly. They are spade. What is the probability that the lost card is also spade?

• (13 - 2) / (52 - 2) = 11 / 50
• 10 years agoHelpfull: Yes(42) No(34)
• ans : 1/4.
  we are concentrated to find the probability of losed card but, before the card was lost ...
  There was total 52 cards...and no of spade cards were...13
  
  so probability is=13/52 =1/4
• 10 years agoHelpfull: Yes(34) No(11)
• ans : 1/4.
  total crds=52
  there vl b 4 sets of cards. 52/4=13
  hence prob= 13/52 =1/4
• 10 years agoHelpfull: Yes(24) No(17)
• 13c3/52c3
  as out of 13 one spade is lost and two are drawn.
  out of 52 cards 3 cards are out
• 10 years agoHelpfull: Yes(14) No(9)
• After losing a spade: no of spades left=12
  and total cards left= 51
  so probability of two cards selected to be spade= 12c2/51c2
• 10 years agoHelpfull: Yes(7) No(4)
• 1)n(s)=51 (since one card has been lost)
  (Given two cards are drawn randomly,possible ways here is 51c2..)
  n(s)=51
  2)n(e)=11c1(3-there exists 13 cards since two cards drawn are spade remaining are 11)..
  n(s)=49
  3)probability of card to be lost is spade is p(e)=11/49
  
• 10 years agoHelpfull: Yes(6) No(2)
• (12/51)*(11/50)
• 10 years agoHelpfull: Yes(5) No(3)
• 11/50 will be the r8 ans..
  as 2 spade are drawn so 11 spades remain from 13 spade and 50 cards remain in the deck
  so the probability that the lost card is spade is 11/50
• 10 years agoHelpfull: Yes(5) No(1)
• ans:12/51...as 1 card from the two is spade ...so left spade is 12...left total
  card is 51..
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  http://www.flashsandy.org/topics/parking
• 10 years agoHelpfull: Yes(4) No(7)
• 11/50 i suppose to be correct ans.
• 10 years agoHelpfull: Yes(3) No(4)
• p(A/B)=probability of A occur if given B occured=p(A and B)/p(B)
  p(A/B)=probability of drawing 2 spades,if lost card is spade=12/51
  p(A and B)=probability of lost card,drawn is spades=?
  p(B)=probability of lost card spade=13/52 =>ans=(13*12)/(52*51)
• 10 years agoHelpfull: Yes(2) No(3)
• cards drawn at random have nothing to do with lost card
  so clearly ans is 1/4
• 10 years agoHelpfull: Yes(1) No(1)
• we have to find the probability of lost card but, before the card was lost ...
  There was total 52 cards...and no of spade cards were...13
  
  so probability is=13/52 =1/4
• 7 years agoHelpfull: Yes(1) No(1)
• prob=(4-2)/(52-2)=1/25
• 10 years agoHelpfull: Yes(0) No(22)
• spade cards are only 13 out of 52
  so , no of ways of losting in 13 is 13c2/52c2
• 8 years agoHelpfull: Yes(0) No(1)
• (13c1*13c1)/52c2=1/4
  that is (13c1) for the lost card which may b spade and another 13c1 for the random card which may b a spade.
• 7 years agoHelpfull: Yes(0) No(0)
• P(A/B)=P(A and B)/P(B) ----> According to conditional probability.
  let A=Spade is lost
  let B= two drawn cards are spade
  conditional prob means prob of a event given that other has occured. here in our case prob of A is to be found out given that B has occured.
  P(A and B)= 12c2/51c2
  P(B)=13c2/51c2(spade is not lost) + 12c2/51c2(spade is lost)
  therefore, P(A/B)=12c2/(13c2+12c2)=11/24
• 7 years agoHelpfull: Yes(0) No(1)
• i can't clear these explaination because question is What is the probability that the lost card is also spade? but you are done this sum before the card was lost ... why what is the reason pls anyone explain me
• 7 years agoHelpfull: Yes(0) No(0)
• Since there are 4 spades and two spades are present even after loss, the probability of lost card to be spade is among remaining two cards
  2/26 = 1/13
• 7 years agoHelpfull: Yes(0) No(1)
• Total number of cards = 52
  
  Total number of cards that are spade = 13
  
  
  Given that the 2 cards drawn are spade
  
  ⇒ The total cards on the deck = 52 - 2 = 50
  
  ⇒ The total number of spades = 13 - 2 = 11
  
  
  Find the probability that the card lost is a spade:
  
  P(spade) = 11/50
  
  
  Answer: The probability is 11/50
• 4 years agoHelpfull: Yes(0) No(0)