The sum of the digits in the decimal form of the product 2399 * 5401 is:

5

7

4

10

between 401 and 3609

• ans:50
  (2400-1)*(5400+1)=(2400*5400)+2400-5400-1
  =12960000-3001=12956999
  sum of digits=1+2+9+5+6+9+9+9=50
• 11 years agoHelpfull: Yes(16) No(2)
• always left hand side = right hand side
  ex 6*3 =18
  9=9
  so here 2399*5401=?
  digital root of2399 is 5
  and that of 5401 is 1
  so 5*1=5
  so left hand side = 5 ,so the whatever be the product the right hand side should also have an answer of 5 .
  so our ans is 5 .
  
• 11 years agoHelpfull: Yes(7) No(1)
• 5.as the product is kknown
• 11 years agoHelpfull: Yes(2) No(2)
• plz xplain?
  
• 11 years agoHelpfull: Yes(1) No(2)