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A sealed envelope contains a card with a single digit written on it. Three of the following statements are true and one is false.
I. The digit is 1.
II. The digit is not 2.
III. The digit is not 9.
IV. The digit is 8.
Which one of the following must necessarily be correct?
II is false
III is true
IV is false
The digit is even.
I is true
Read Solution (Total 12)
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- III is true
since when 3 is wrong then there are 2 possibilities that 1 or 8
which is not possible - 11 years agoHelpfull: Yes(23) No(4)
- i think its dummy question not getting it
- 11 years agoHelpfull: Yes(8) No(4)
- correct stmt is III is true ,bcoz if any of the II and III become false ,at any tym 3 stmts cant b true
- 11 years agoHelpfull: Yes(7) No(0)
- IV is false
- 11 years agoHelpfull: Yes(3) No(4)
- the digit is one so (I is true)
- 11 years agoHelpfull: Yes(3) No(4)
- III is true cuz 1 or 8 cant both be true at the same time
- 11 years agoHelpfull: Yes(2) No(1)
- ans: IV is false
bcs:
when iv is false than only other 3 statement are true - 11 years agoHelpfull: Yes(2) No(2)
- the digit is even
- 11 years agoHelpfull: Yes(1) No(2)
- look the naswers are both 1 is true and 4 is false...so i guess its a dummy one
- 11 years agoHelpfull: Yes(0) No(0)
- I is true
can be deduced easily - 11 years agoHelpfull: Yes(0) No(2)
- III is true
- 11 years agoHelpfull: Yes(0) No(0)
- The answer is III is true (The digit is not 9)
Consider the following scenario: ( Three of the following statements are true and one is false.)
If the digit is not 9 (True)
The digit is not 2.(True)
The digit is 8 (True)
so obviously The digit is 1(False)-
per the question - 4 years agoHelpfull: Yes(0) No(0)
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