There are 3 groups A,B,C
2 members belong to all the three
3 members belong to A&B
3 members belong to B&C
3 members belong to C& A
minimum possible number of members in any three.

• 2 member belongs to all three, so (3-2)=1 are in only a & b; similarly 1 in only a & c; 1 in only b & c;(use ven diagram).so min no=2+1+1=4 ans.
• 11 years agoHelpfull: Yes(15) No(0)
• min possible mem= 4 in each set
• 11 years agoHelpfull: Yes(4) No(1)
• 4 might be the minimum answer
• 11 years agoHelpfull: Yes(3) No(1)
• 8 will be the answer
• 11 years agoHelpfull: Yes(3) No(8)
• ANS =4
  i=INTERSECTION
  n(A i B i C)-n(A i B)-N(A i C)=2-3-3=-4
  FOR MINIMUM POSSIBLE NUMBER THESE (-4) IS TO SUBTRACTED FROM 0=0-(-4)=4
• 11 years agoHelpfull: Yes(3) No(3)
• group1:A,B,C,E
  group2:A,B,C,D
  group3:A,B,C,E
  so ans is 4
• 11 years agoHelpfull: Yes(2) No(1)
• 5. By taking ven diagram of 3 group in that we can fix the given combinations and as given min in problem we are considering members belong to only single group is zero.... So answer is 5
• 11 years agoHelpfull: Yes(1) No(5)
• ans is 5
  
• 11 years agoHelpfull: Yes(1) No(0)