B moves by taking 3 steps forward and 1 step backward each step in one second He walks up a

for every 4sec 2steps moved(1+1+1-1).
In 116 second 58steps are taken.
another two second 2 steps taken.
total no steps=(58+2)=60
now let the speed of escalator is x
so
40(k(step/second)+2step/4second)=60
on solving
k=1step/second
10 years agoHelpfull: Yes(3) No(0)
4 sec=2 step
so total 59 step
in 40 sec total =20step
now require 40 step in 40 sec so
1 ans=1
11 years agoHelpfull: Yes(2) No(8)
person takes 3 steps forward and 1 step back so his speed is 2 steps per 4 second
or speed of person= 0.5 steps/second
this means he is covering 1 step in 2 seconds so time at every step would be like:
2 4 6 8 ........116
no of steps= 116*speed of person= 116 * 0.5= 58
now for remaining two seconds, as we know he takes three steps at a time, each in 1 second
so, he would cover two steps in 2 seconds as a part of his 3 steps forward and 1 step back..
so total no of steps= 58+2=60

let speed of escalator be x,
60=(x-0.5)*40
x=2 steps/second
10 years agoHelpfull: Yes(0) No(2)
sry it wud be
60=(x+0.5)*40
so x=1 step/seec
10 years agoHelpfull: Yes(0) No(0)
B moves 3steps forward and 1step backward.therefore he takes 4sec for 2steps.for 118 sec he moves 59 step by walk in a escalator..in a moving escalator it takes only 40sec.therefore speed of escalator is 59/40=1.475steps/sec
8 years agoHelpfull: Yes(0) No(0)

B moves by taking 3 steps forward and 1 step backward (each step in one second) He walks up a stationary escalator in 118 sec. However on moving escalator he takes 40 sec to reach top.Find speed of escalator.