In How many ways we can Give 7 different things to 3 people. All of them must get at least one?

• 15 ways...
  (1,1,5)-3ways
  (1,2,4)-6ways
  (1,3,3)-3ways
  (2,2,3)-3ways
• 11 years agoHelpfull: Yes(27) No(6)
• n-r
  C ,where n=7 & r=3
  r-1
  so answer= 6C2 = 6*5/2*1=15
• 11 years agoHelpfull: Yes(16) No(2)
• ans is 6c2
• 11 years agoHelpfull: Yes(10) No(1)
• Each of the 7 things can be dealt in 3 ways
  
  So answer is 3^7
• 11 years agoHelpfull: Yes(6) No(17)
• since it is a positive integer solution , so can apply the formulae-
  n-1cr-1 thus, 7-1C3-1=15
• 11 years agoHelpfull: Yes(3) No(1)
• @ankita:
  That formula is used when u have identical/similar things. Question has 7 different things
• 11 years agoHelpfull: Yes(2) No(0)
• 7C3*3!*3^4
  this is the right answer because u need to choose 3 things among those 7 so 7C3,and then give these things to each people and these 3 arrange with 3!. and rest 4 things given according to 3^4.
• 11 years agoHelpfull: Yes(2) No(2)
• 4^7 -1 is da answer.
  each thing cn b given to either no1 or to 1st person or to 2nd or to 3rd. thus there r 4 possibilities for each item. thus 4^7. however we have to exclude the possibility that no item is given to anyone. so 4^7-1.
• 11 years agoHelpfull: Yes(1) No(1)
• first we give 1 different thing to each person in 3! ways then we will have 4 things remaining 4 things in 3*3*3*3 ways hence 3!*3^4 is the answer
• 11 years agoHelpfull: Yes(1) No(2)
• answer is 6c2
• 11 years agoHelpfull: Yes(1) No(0)
• (n-1)C(r-1)=6C2=15
• 8 years agoHelpfull: Yes(1) No(0)
• (1,3,3)is also a way
  
• 11 years agoHelpfull: Yes(0) No(2)
• IN 3C2 WAYS WE CAN GIVE 6 THINGS TO 3 PEOPLE 2 EACH.,SO THAT THE REMAINED 1 THING CAN BE GIVEN TO 3 PEOPLE IN 3C1 WAYS.,SO 3C2=3 AND 3C1=3........3*3=9 WAYS
• 11 years agoHelpfull: Yes(0) No(8)
• 24 ways... as 7 are different objects not identical
  (1,1,5)-6ways
  (1,2,4)-6ways
  (1,3,3)-6ways
  (2,2,3)-6ways
  if they are identical then (n-1)C(r-1)
• 10 years agoHelpfull: Yes(0) No(0)