Two parallel chords of circle of length 30 cm and 24 cm, radius of circle is 20 cm. Find the distance between the two chords

• ANS:
  SHORTEST DISTANCE= 2.77CM
  LONGEST DISTANCE= 29.23CM
  distance betweenONE CHORD AND CENTER=SQRT(RADIUS^2-(CHORD LENGTH/2)^2)
  DISTANCE D1=SQRT((20^2)-(30/2)^2)
  D1=SQRT(400-225)=SQRT(175)
  D1= 13.23
  DISTANCE D2=SQRT((20^2)-(24/2)^2)
  D2=SQRT(400-144)=SQRT(256)
  D2= 16
  shortest distance between parallel chords is=D2-D1
  =16-13.23
  =2.77CM
  LONGEST distance between parallel chords is=D2+D1
  =16+13.23
  =29.23CM
• 11 years agoHelpfull: Yes(25) No(0)
• use Pythagoras therom
  20^2=15^2+x^2 is eql to 13.22
  20^2=12^2+y^2 is eql to 16
  x+y= 29.22
• 11 years agoHelpfull: Yes(7) No(0)
• the ans will either be 29.22 or 2.78 depending upon whether the chords r on the same side or opposite side
• 11 years agoHelpfull: Yes(3) No(0)
• first consider the length of the chord 30cm say AB. the mid point of AB is m1.now draw a line from center of the circle say O to point A.now length of OA(radius)=20cm and AM=15cm(half of chord 30cm),,now using pythogras theorem we can find the distance between center of circle O to M OM distance is 13.28cm..
  likewise consider 2nd chore as CD=20cm middle point as M2..for same radius draw line from O to C..OC is radius..now u know CM2=12cm OC=20cm the we can find OM2 as 16cm
  for total distance add OM+OM1=113.288+16=29.228cm
  
• 11 years agoHelpfull: Yes(1) No(0)
• AS R=20CM.,FOR A COMPLETE CIRCLE 2R=40 CM.,SO THAT THE DISTANCE CHORDS WILL BE 40 CM
• 11 years agoHelpfull: Yes(0) No(9)