In school there are some bicycles and 4 wheeler wagons.One tuesday,there are 190 wheels in the campus.how many bicycles are there?

• actually this question shud have options,there are many solutions.
  say 2x+4y=0
  consider y=0
  so x,y=95,0
  as multiple of 2,4 is 4, the x and y values are also reduced in the same order like
  93,1
  91,2
  89,3
  .
  .
  .
  goes on
  options shud be given
• 11 years agoHelpfull: Yes(16) No(2)
• question is incomplete
• 11 years agoHelpfull: Yes(5) No(1)
• let no of bicycle is x and wagons is y
  so 2x+4y=190
  if we take x=69 and y=13 , it satisfy the question...
  so no of bicycle is 69
  
• 11 years agoHelpfull: Yes(4) No(9)
• 69 bicycle and 13 car
• 11 years agoHelpfull: Yes(0) No(9)
• 65 bicycles
• 11 years agoHelpfull: Yes(0) No(7)
• can any1 explain in detail??
• 11 years agoHelpfull: Yes(0) No(1)
• pls xplIn sltion in detail
• 11 years agoHelpfull: Yes(0) No(1)
• 95.,AS 2 WHEELS PER EACH BICYCLE.,190/2=95.,
• 11 years agoHelpfull: Yes(0) No(8)
• prime factors of 190 are 2,5,19.
  19*2=38
  190-38=152
  152/4=38
  hence 19 bicycles n 38 4 wheel wagons :p
• 11 years agoHelpfull: Yes(0) No(1)
• If there are 20 bicycles, they would have 40 wheels, leaving 150 wheels for the wagons, but 150 is not divisible by 4.
  
  If there are 18 bicycles, they would have 36 wheels, leaving 154 wheels for the wagons, but 154 is not divisible by 4.
  
  19 and 15 are both possible. More information is needed to choose one of those options.
• 9 years agoHelpfull: Yes(0) No(0)