Two breakers are kept on a table. the capacity of the first breaker is x liters and that of the second breaker is 2x. Two thirds of the 1st breaker and one fourth of the 2nd breaker is filled with wine. The remaining space in both breakers is filled with water. If the content in these breakers are mixed in a larger breaker of volume 3x, What is the proportion of wine in the breaker?
a) 11/12
b) 11/36
c) 7/6
d) 7/18

• 2/3+1/2(1/4th of 2x =1/2 of x)=7/6. when pored in breaker of vol 3x then d proportion will be 7/6 *1/3=7/18
  
• 10 years agoHelpfull: Yes(31) No(2)
• capacity of the breakers are x,2x,3x
  let take x=30 and 2x=60 3x=90
  2/3*30=20,1/4*60=15 total part of wine is 35/90=7/18
• 10 years agoHelpfull: Yes(29) No(0)
• 7/18
  vol of wine in beaker with vol x=2x/3
  
  vol of wine in beaker with vol 2x=x/2
  total vol of wine=2x/3+x/2=7x/6
  so,proportion of wine in 3x vol beaker=3x*7/18
  
• 10 years agoHelpfull: Yes(13) No(15)
• what is the correct answer for this question.
• 10 years agoHelpfull: Yes(5) No(0)
• capacity of beakers x,2x,3x
  2/3(x)+1/4(2x)=7x/6
  wine proportion is =7x/(6*3x)=7/18
• 10 years agoHelpfull: Yes(2) No(0)
• ans is: 11/36 bcz 2/3 in 1st and 1/4 in 2nd gives 11/12 part of wine and this becomes 11/36 part in 3x
• 10 years agoHelpfull: Yes(1) No(6)
• 2/3+1/4=11/12
• 10 years agoHelpfull: Yes(1) No(12)