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What is the sum of 28 terms of the series,
(k^2)*(28Ck),
where (28Ck) is the number of ways of choosing k items from 28 items?
Read Solution (Total 8)
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- @SRIRAM KUMAR MANNAVA : plz explain how this formula came????
- 11 years agoHelpfull: Yes(7) No(0)
- @AKASH SINGH : first of all learn to behave... if i m not getting sumthing i will ask.. do i hv to take ur permission fr that???
- 11 years agoHelpfull: Yes(6) No(0)
- The solution is basically a formula n(n+1)2^n-2 where n=28 => 28*29*2^26= 14*29*2^27= 406*2^27
- 11 years agoHelpfull: Yes(5) No(5)
- @SRIRAM KUMAR MANNAVA
IN THE FORMULA n(n+1)2^(n-2)
U HAVE TAKEN n=28 THE n-2=26 NOT 27
U HAVE STATED IT AS 27 - 11 years agoHelpfull: Yes(2) No(3)
- don't ask this type of rubbish question....and answer will be 406*2^27.....
- 11 years agoHelpfull: Yes(1) No(5)
- @DIVYA that was a formula I've read in my text book and applied to this problem :)
- 11 years agoHelpfull: Yes(1) No(0)
- @divya..did this q really came in tcs????
- 11 years agoHelpfull: Yes(1) No(0)
- @SRIRAM : okk.. thanx.. :)
- 11 years agoHelpfull: Yes(0) No(0)
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