Total number of 4 digit number do not having the digit 3 or 6.

• consider 4 blanks _ _ _ _
  1st blank can be filled in 7c1 ways (0,3,6 are neglecetd)
  2st blank can be filled in 8c1 ways (0 considered along with 1,2,4,5,7,8,9)
  3st blank can be filled in 8c1 ways
  4st blank can be filled in 8c1 ways
  therefore total 4 digit num without 3 and 6 is 7*8*8*8=3584
• 11 years agoHelpfull: Yes(39) No(5)
• 7*8*8*8=3584
• 11 years agoHelpfull: Yes(9) No(3)
• 8*9*9*9=5832(considering only 3)
  8*9*9*9=5832(considering only 6)
  7*8*8*8=3584(consider 3&6)
  ans=5832+5832-3584
  =8080
• 11 years agoHelpfull: Yes(8) No(14)
• 4 digit means 4 places, and total digits are 0-9 =(10)
  after excluding 3 & 6 numbers =(8)
  1st place 1,2,4,5,7,8,9 = 7 (excluding 0, as its 1st place)
  2nd place 7+1 =8
  3rd place 7+1 =8
  3rd place 7+1 =8
  so numbers =7*8*8*8 =3584
• 11 years agoHelpfull: Yes(6) No(3)
• no of 4digit nos =9*10*10*10= 9000
  no not having 3 or 6 thn we have only 7 nos 4 thousands place and 8 for rest places
  no of such nos= 7*8*8*8=3584
• 11 years agoHelpfull: Yes(2) No(2)
• answer is 8020
  
• 11 years agoHelpfull: Yes(0) No(4)
• _ _ _ _
  first blank can be filled in 7 ways excluding 0,3,6
  second, third and fourth can be filled in 8 ways (as we can have 0 in any of these positions)
  so total ways will be 7*8*8*8= 3584 ways
• 5 years agoHelpfull: Yes(0) No(0)