How many 9 digits number can be formed out or 1,2,3,4,5 if repetition is allowed and the number is divisible by 4

• if a number is divisible by 4 then the last two numbers should be divisible by 4.
  so the divisible numbers should end with either 12,24,32,44,52.the rest of the 7 numbers can be arranged in (5)^7 ways.so for all of the above 5 cases its 5*(5)^7=(5)^8=390625
• 11 years agoHelpfull: Yes(20) No(1)
• we make a 9 digit no and that no is divisible by 4 if no is divisble bye 4 then last two digit divisible by 4 then no ens with 12 ,24,32,44,52 amd remaining 7 plces can be arranged in (5)^7ways and no ends 12,24,32,44,52 then it creat a 5 cases then ans is (5)^7*5=390625
• 11 years agoHelpfull: Yes(8) No(0)
• Ans should be 4*5^7
• 11 years agoHelpfull: Yes(1) No(2)
• sorry i haven't considered 44 case answer should be 5^8 only
• 11 years agoHelpfull: Yes(1) No(1)
• number is divisible by 4,so it must be end with either 2 or 4 of given digits. and 8 places will be like 5*(5)^7=390625
• 11 years agoHelpfull: Yes(1) No(0)
• in last two digits it can be filled in 5 ways and in 7 diguts we can fill in 4^6 ways so in total it can be formed in 20480 ways
• 11 years agoHelpfull: Yes(0) No(2)