if a,b,c,d,e are distinct numbers if(75-a)(75-b)(75-c)(75-d)(75-e)=2299 then a+b+c+d=?

• 2299 = 11×11×19×1×1=11× −11×19× −1×1=
  Two of the terms in the given expression should equal to 1. As all the digits are distinct, two of the terms should be negative.
  One possible solution = (75 - 64)(75 - 56)(75 - 86)(75 - 74)(75 - 76)
  Then a + b + c + d + e = 64 + 56 + 86 + 74 + 76 = 356
  But as the sum of only 4 terms was asked, we have to subtract one term.
  So given answer can be one of 292, 306, 270, 282, 280
• 11 years agoHelpfull: Yes(32) No(1)
• 2299 can be written as 19*121=19*11*11=19*11*(-11)*(-1)*1
  now 75-a*75-b*75-c*75-d*75-e
  equating corresponding values we get a=56,b=64,c=86,d=76,e=74...on adding we get 356....this is procedure... not sure of calculation
• 11 years agoHelpfull: Yes(10) No(1)
• factors of 2299 are 11, 19, 1,-1,-11,-19 so a+b+c+d+e=86+76+74+64+56=356
  take any 4 of 5 and you will get the answer
• 11 years agoHelpfull: Yes(3) No(0)
• ans=256
  64+64+56+75
• 11 years agoHelpfull: Yes(0) No(1)
• ans = 334
  
• 11 years agoHelpfull: Yes(0) No(3)
• since
  2299=19*11*11
  we can write
  19*11*11*(-1)*(-1)
  compare with (75-a)*(75-b)*(75-c)*(75-d)*(75-e)
  we get
  a=56,b=64,c=64,d=76,e=76
  hence
  a+b+c+d=56+64+64+76=260
  tell me is it right
• 11 years agoHelpfull: Yes(0) No(3)
• @Dipak ..can you explain me that why are u putting -ve sign before 11 and 1 can't we write it only 11 *1
• 11 years agoHelpfull: Yes(0) No(1)
• 258
  74+64+64+56
• 11 years agoHelpfull: Yes(0) No(2)
• 75 - 64)(75 - 56)(75 - 86)(75 - 74)(75 - 76)
  Then a + b + c + d + e = 64 + 56 + 86 + 74 + 76
  we have only four terms so these any one may be the answer 292, 306, 270, 282, 280
  
• 10 years agoHelpfull: Yes(0) No(1)