if t1 7 t2 7 7 t3 7 7 7 and so on The digit at ten s place of

0 will be at ten's place
bcoz t1000=7^1000.
cyclicity of 7 is 07, 49, 43, 01 (considering only last two digits of each)
hence 1000%4=0
thus ans is 07...thus at ten's place its 0
11 years agoHelpfull: Yes(10) No(0)
7^1=07
7^2=49
7^3=243
so on we get repeated numbers for the both units and ten digit numbers so the number would be repeating them selves so it would be zero for tens place and 7 for units place
11 years agoHelpfull: Yes(4) No(1)
here 7^1=7
7^2=49..unit digit =9
7^3=343..unit digit =3
7^4=343*7=..unit digit=1
now 7^5= unit digit 187=7
thus 1000%4=0
therefore 7^1000=unit digit 7
Answer 7
11 years agoHelpfull: Yes(2) No(3)
is it 7^7 or 7^2????????
11 years agoHelpfull: Yes(2) No(0)
I think the ans will also 7.bcs t1000 means 7^1000.am nt sure.is it??
11 years agoHelpfull: Yes(1) No(3)

if t1=7,t2=7^7,t3=7^7^7 and so on.The digit at ten's place of t1000 is???