Consider all permutations ( i.e arrangements ) of the digits 1, 2, 3 we will say that a hit has been scored if at least one digit occurs in its proper position ( i.e 1 occurs in the first position, 2 occurs in the second position and 3 occurs in the third position ). In how many ways of this permutation can be scored
option
a) 4
b) 2
c) 1
d) 3

• 4 ways ....123,132,213,321
• 11 years agoHelpfull: Yes(7) No(1)
• ans is 4..combinations are 321,231,123,312
• 11 years agoHelpfull: Yes(2) No(1)
• i think the ans will be 4. nt sure.. becs if i fix 1's position then it wll cm 123 or 132 if i fix 2's position den it wll come 123 321 and if i fix 3's position it will cm 123 231.as they said atlest one ocurs in its proper position we can also keep it more than one tym.123 is coming fr every 3 cases if we keep 123 in its proper position den we will take it as 1 for all 3..now left 231 321 132 total 4.
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 4;123,321,213,132
• 11 years agoHelpfull: Yes(0) No(0)
• 4 ways i.e 123,132,321,213
• 11 years agoHelpfull: Yes(0) No(0)
• is 111,222,333 are possible or not
• 11 years agoHelpfull: Yes(0) No(1)