An army camp has provisions for 52 days 17 days later 300 new recruits join the camp and the remaining

750
let the number of people be x and after 17 days they have still 35 provisions left.
now 300 added, so x+300 which last for 21ays ie 21(x+300). This should be equal to 35x (if no new member is added). Equate them, we'll get x=450. after adding 300 we have 750
10 years agoHelpfull: Yes(36) No(1)

let the initial people be x.
52x=17x+21(300+x)
x=450 initially
but total no. of people are 450+300=750
10 years agoHelpfull: Yes(21) No(0)
450
17days remaning 35days;let no of people x;35x=(total no of peple)(no of days)
=21(x+300)
53x=21(x+300)
x=450
10 years agoHelpfull: Yes(3) No(0)
750 should be the answer i haven't mentioned those other 300 in my answer
10 years agoHelpfull: Yes(3) No(0)
let there are x recruits in camp
so x*52=x*17+(x+300)*21
so x =450
10 years agoHelpfull: Yes(1) No(0)
let no.of men be x.after 17 days they left with 35days provisions
35x.300 new men were added hence it is x+300 and provisions left for 21 days hence is 21(x+300) by equating 35x=21(x+300).x=450 no.of men=300+450
10 years agoHelpfull: Yes(1) No(0)

An army camp has provisions for 52 days. 17 days later, 300 new recruits join the camp and the remaining provisions will now last only 21 days. How many recruits are there in the camp.