Consider all permutations (i.e. arrangements) of the digits 1, 2 and 3. We will say that a hit has been scored if at least one digit occurs in its proper position in the permutation, i.e. if 1 occurs in the first position, or 2 in the second position, or 3 in the third position. In how many of these permutations is a hit scored?

• The ans is 4, because the possible arrangements are 123,132,231,213,312,321 and among these the hits are 123,132,321,213...
  so ans is 4
  
• 11 years agoHelpfull: Yes(19) No(0)
• the ans is 4
• 11 years agoHelpfull: Yes(17) No(2)
• plzz clarify the ans.....3 or 4 is ok
  
• 11 years agoHelpfull: Yes(2) No(0)
• sorry answer is 4 my mistake friends....
• 11 years agoHelpfull: Yes(1) No(0)
• really sry i posted the wrong ans...The ans is 4 only.....
• 11 years agoHelpfull: Yes(1) No(1)
• the possible permutations are 123,132,231,213,312,321. so among these 123,132,213 are hit scored.so 3 is the ans
  
• 11 years agoHelpfull: Yes(0) No(9)
• there are 123,132,213,231,312,321 but from that only 123,132,213 digit is answer
  because in 123-1 is on 1st place
  because in 132-1 is on 1st position
  because in 213-3 is on 3rd place
• 11 years agoHelpfull: Yes(0) No(2)
• 4/6
• 11 years agoHelpfull: Yes(0) No(0)