The average of A,B,C is 31. And average of B, C and D is 30. If a is 22. Then find out D.

• A+B+C=3*31
  B+C+D=3*30
  SUBTRACTING BOTH EQN
  A-D=3
  D=22-3=19
• 11 years agoHelpfull: Yes(19) No(2)
• ans.=19.
  average of a,b,c is 31 ,it means a+b+c=93
  average of b,c,d=30,it means b+c+d=90
  given a=22
  22+b+c=93,,b+c=71
  putting value of b+c in b+c+d=90
  71+d=90 ,,hence D=90-71=19;
• 11 years agoHelpfull: Yes(3) No(1)
• a+b+c=93
  b+c+d=90
  a=22 so b+c=71
  so d=19
  
• 11 years agoHelpfull: Yes(2) No(2)
• a+b+c=3*31=93
  b+c+d=3*30=90
  sub the 2 eqn,
  a-d=3
  22-d=3
  d=19
• 11 years agoHelpfull: Yes(2) No(0)
• ANS: 18
  a+b+c = 93
  b+c+d = 90
  a-d = 3
  22-d = 3
  d=22
• 11 years agoHelpfull: Yes(1) No(14)
• ANS: 19
  a+b+c = 93
  b+c+d = 90
  a-d = 3
  22-d = 3
  d=19
• 11 years agoHelpfull: Yes(1) No(0)
• sorry the caluculation i did before is wrong
  22 -d=3
  d=19
• 11 years agoHelpfull: Yes(1) No(1)
• solving th give two eq we get
  A-D=3 ,so a=22
  22-3=19
  
• 11 years agoHelpfull: Yes(1) No(1)
• answer is 19.
  given (a+b+c)/3=31 and a=22 by solving this b+c=71.
  (d+b+c)/3=30 by solving it d=19.
• 11 years agoHelpfull: Yes(1) No(1)
• The value of D= 19 Ans.
• 11 years agoHelpfull: Yes(0) No(0)