A man purchased cow and horse at rs 200000 and sold cow for 20% profit and horse at a loss, if overall gain is 4000 find the selling price of cow and horse

• Let us suppose the cost price of a horse be Rs.x then the cost price of a cow will be Rs.(200000-x).
  Now according to question we have....
  x*(80/100)+(200000-x)*(120/100)=204000
  => x=90000
  So the selling price of a horse will be =90000*(80/100)=72000
  
• 10 years agoHelpfull: Yes(24) No(4)
• Answer is selling price of cow is 132000 and horse is 72000
  let price of cow is 'x' and price of horse is 'y'
  two eqns are given
  x+y=200000
  1.2x+0.8y=204000
  solving these we get x=110000 and y=90000
  selling price of cow is 1.2*110000=132000
  selling price of horse is 0.8*90000=72000
  
• 10 years agoHelpfull: Yes(16) No(0)
• let horse is x,then cow cost is 200000-x
  total gain=(200000-x)*20/100-x*20/100=4000
  then x=90,000
  and cow cost should be 1,10,000.
  
• 10 years agoHelpfull: Yes(8) No(6)
• let us suppose the CP of cow is x and the horse is (200000-x)
  we know that overall gain is 4000 i.e.
  (profit in case of cow-loss in case of horse)=4000
  for cow
  20=profit*100/CP
  profit=20*x/100
  for horse,
  loss=10*x/100
  so,
  (x/5)-((20000-x)/10)=4000
  it will give you x
  x=80000
  
• 10 years agoHelpfull: Yes(2) No(5)
• C+ H= 2,00,000RS.....................1
  1.2C+.8H=204000RS............2
  C=110000RS, H=90000RS
  SP FOR COW=1.2*110000=132000RS
  SP FOR HORSE=0.8*90000RS=72000RS
  
• 9 years agoHelpfull: Yes(2) No(0)
• Answer is 72000.
• 10 years agoHelpfull: Yes(1) No(1)