A beaker contains 180 liters of wine each day 60lts of wine is replaced with same amount of water what is the amount of wine after 3 days?

• use formula:
  remain_volume = initial_volume(1-(replacement_volume/final_volume))^days
  so
  remain_volume = 180(1-60/180)^3= 53.33
• 11 years agoHelpfull: Yes(23) No(3)
• It is said that 60 lts of Wine is replaced , not the mixture, so shouldn't the answer be 0 ?
• 10 years agoHelpfull: Yes(8) No(0)
• 53.4 approximately.
  formula : x(1-y/x)^n
  x=160. y= 60 n = 3
• 11 years agoHelpfull: Yes(5) No(5)
• Answer will be 0.
  
  1st day : 120 L wine and 60 L water .
  2nd day : 60 L wine 120 L water
  3rd day : 0 L wine and 180 L water.
  
  they have;nt written wine from the mixture (wine+water) otherwise we may have calculated with the help of ratio.
• 10 years agoHelpfull: Yes(0) No(5)